A 9 kg mass experiences a horizontal force of 6 N to the right and a force of 4 N to the left. What is the acceleration?

A 9 kg mass experiences a horizontal force of 6 N to the right and a force of 4 N to the left. What is the acceleration?

• A. 0.22 m/s^2 to the right
• B. 0.44 m/s^2 to the left
• C. 0.67 m/s^2 to the right
• D. 0.11 m/s^2 to the right

Answer: (A)

Acceleration is determined by the net force acting on an object and its mass, via a = F_net / m, and it points in the direction of the net force. Here, the horizontal forces are 6 N to the right and 4 N to the left, so the net force is 6 − 4 = 2 N to the right. Using the mass 9 kg, the acceleration is a = 2 N / 9 kg ≈ 0.222 m/s^2. So the object accelerates to the right at about 0.22 m/s^2.

Acceleration is determined by the net force acting on an object and its mass, via a = F_net / m, and it points in the direction of the net force. Here, the horizontal forces are 6 N to the right and 4 N to the left, so the net force is 6 − 4 = 2 N to the right. Using the mass 9 kg, the acceleration is a = 2 N / 9 kg ≈ 0.222 m/s^2. So the object accelerates to the right at about 0.22 m/s^2.